Optical Illusion

[privateer]

[Physics_Rulez]

den mou fainontai gia idia pantws... mipws einai moufa?

 

***edited

ki omws einai idia... to dokimasa me to paint, alla kai me to photoshop :!: :!: :!: :!: :!: kai den tou fainetai...

[mentor]

Mexri kai stoixhma vazei kaneis oti den einai idia ta xrwmata sta sygkekrimena koytakia!

 

Kalo!

[spiros]

den to katalabenw.

[Knorcedger]

οντως ρε παιδια, αφου ειναι διαφορετικα, που ειναι η illusion?????

[Dionisos]

Einai "aplo"...

 

Phra to xrwma tou B kai travhksa mia grammh pros to A. Ola afta me to "Paint".

[spiros]

opws to katalabenw, den einai ilussion!!!

sthn ousia pezei me thn enoia ths skias, afou edw h "skia" anti na skourainei, anoigei ta xrwmata...

[_DiMoN_]

Εκτυπώστε το και κόψτε μ' ένα ψαλίδι τα Α και το Β και μετά βάλτε τα δίπλα δίπλα...

[HexStatic]

Apisteuto!!!

[privateer]

 

The reason the two regions look different even though they are the same color is because of lateral inhibition. It's the way your visual system does edge detection. The photoreceptors in your eyes are wired together in such a way that the input to one receptor affects the nearby receptors because it affects how much one photoreceptor inhibits the ones around it. Essentially, an object's surrounding affect how your perceive it.

Because square B is surrounded by darker squares as well as the shadow from the pillar, the input to the eyes from square B is inhibited less. This is why it appears to be white. However, square A is surrounded by lighter squares and since that causes the signals from square A to be inhibited more which is why they appear to be darker.

And when _leech_ blacks out everything except the two squares, the visual signals are both inhibited the same amount, which is why they now appear to be the same.

[spiros]

xm... twra to epiasa... episis doulebei kai an kalispete ola ta ipolipa kai afhsete mono ta A+B akalipta... POLI EKSIPNO!